lead (II) sulfate → PbSO4
acetic acid → CH3COOH
Balanced Reaction: H2SO4(aq) + Pb(CH3COO)2(aq) → PbSO4(s) + 2 CH3COOH(aq)
• PbSO4(s) from H2SO4(aq)
molar mass PbSO4 = 303.26 g/mol
molae mass H2SO4 = 98.079 g/mol
You may want to reference (Pages 106 - 110)Section 3.7 while completing this problem.
Calculate the number of grams of lead(II) sulfate present in the mixture after the reaction is complete.
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