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Problem: Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. 5.50 g of sulfuric acid and 5.50 g of lead(II) acetate are mixed.You may want to reference (Pages 106 - 110)Section 3.7 while completing this problem.Calculate the number of grams of lead(II) acetate present in the mixture after the reaction is complete.

FREE Expert Solution

sulfuric acid → H2SO4(aq)
lead(II) acetate → Pb(CH3COO)2(aq)
lead(II) sulfate → PbSO4(s)
acetic acid → CH3COOH(aq)


The balanced reaction is:

H2SO4(aq) + Pb(CH3COO)2(aq) → PbSO4(s) + 2 CH3COOH(aq)

From the reaction:

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Problem Details
Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. 5.50 g of sulfuric acid and 5.50 g of lead(II) acetate are mixed.

You may want to reference (Pages 106 - 110)Section 3.7 while completing this problem.

Calculate the number of grams of lead(II) acetate present in the mixture after the reaction is complete.

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