sulfuric acid → H2SO4(aq)
lead(II) acetate → Pb(CH3COO)2(aq)
lead(II) sulfate → PbSO4(s)
acetic acid → CH3COOH(aq)
The balanced reaction is:
H2SO4(aq) + Pb(CH3COO)2(aq) → PbSO4(s) + 2 CH3COOH(aq)
From the reaction:
You may want to reference (Pages 106 - 110)Section 3.7 while completing this problem.
Calculate the number of grams of lead(II) acetate present in the mixture after the reaction is complete.
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