Ch.3 - Chemical ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. 5.50 g of sulfuric acid and 5.50 g of lead(II) acetate are mixed.Calculate the numbe

Solution: Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. 5.50 g of sulfuric acid and 5.50 g of lead(II) acetate are mixed.Calculate the numbe

Problem
Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. 5.50 g of sulfuric acid and 5.50 g of lead(II) acetate are mixed.


Calculate the number of grams of sulfuric acid present in the mixture after the reaction is complete.

Solution

The chemical reaction is:

H2SO4(aq) + Pb(C2H3O2)2(aq) → PbSO4(s) + HC2H3O2(aq)

Balancing this gives us:

H2SO4(aq) + Pb(C2H3O2)2(aq) → PbSO4(s) + 2 HC2H3O2(aq)

We're being asked to determine the mass of H2SO4 present in the mixture after the reaction is complete. This means that H2SO4 is the excess reactant while Pb(C2H3O2)2 is the limiting reactant.

The molar mass of H2SO4 is 2(1.01 g/mol H) + 32.06 g/mol S + 4(16.00 g/mol O) = 98.08 g/mol. The molar mass of Pb(C2H3O2)2 is 207.20 g/mol Pb + 4(12.01 g/mol C) + 6(1.01 g/mol H) + 4(16.00 g/mol O) = 325.30 g/mol. From the balanced chemical equation, 1 mole of Pb(C2H3O2)2 reacts with 1 mole of H2SO4.

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