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Problem: Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction: 8 H2S(g) + 4 O2(g)  →  S8(l) + 8 H2O(g). Under optimal conditions the Claus process gives 98% yield of S8 from H2S.If you started with 40.0 grams of H2S and 55.0 grams of O2, how many grams of S8 would be produced, assuming 97 % yield?

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Balanced Reaction: 8 H2S(g) + 4 O2(g)  →  S8(l) + 8 H2O(g)

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Problem Details

Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction: 8 H2S(g) + 4 O2(g)  →  S8(l) + 8 H2O(g). Under optimal conditions the Claus process gives 98% yield of S8 from H2S.

If you started with 40.0 grams of H2S and 55.0 grams of O2, how many grams of S8 would be produced, assuming 97 % yield?

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