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Problem: When benzene (C6H6) reacts with bromine (Br2), bromobenzene (C6H5Br) is obtained: C6H6 + Br2 → C6H5Br + HBrIf the actual yield of bromobenzene was 58.6 g, what was the percentage yield?

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Balanced Reaction: xC6H6 + Br2 → C6H5Br + HBr

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When benzene (C6H6) reacts with bromine (Br2), bromobenzene (C6H5Br) is obtained: C6H6 + Br2 → C6H5Br + HBr

If the actual yield of bromobenzene was 58.6 g, what was the percentage yield?

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