Problem: You may want to reference (Pages 103 - 105)Section 3.6 while completing this problem.Detonation of nitroglycerin proceeds as follows: 4 C3H5N3O9(l) → 12 CO2(g) + 6 N2(g) + O2(g) + 10 H2O(g). If each mole of gas occupies 56 L under the conditions of the explosion, how many liters of gas are produced?

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The given reaction is:

4 C3H5N3O9(l) → 12 CO2(g) + 6 N2(g) + O2(g) + 10 H2O(g)

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You may want to reference (Pages 103 - 105)Section 3.6 while completing this problem.
Detonation of nitroglycerin proceeds as follows: 4 C3H5N3O9(l) → 12 CO2(g) + 6 N2(g) + O2(g) + 10 H2O(g). If each mole of gas occupies 56 L under the conditions of the explosion, how many liters of gas are produced?

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