**Step 1: **87.5% N and 12.5% H by mass.** **Recall that ** mass percent** is given by:

$\overline{){\mathbf{\%}}{\mathbf{}}{\mathbf{mass}}{\mathbf{=}}\frac{\mathbf{mass}\mathbf{}\mathbf{of}\mathbf{}\mathbf{X}}{\mathbf{total}\mathbf{}\mathbf{mass}}{\mathbf{\times}}{\mathbf{100}}}$

Assuming we have **100 g** of the compound, this means we have **87.5 g N** and **12.5 g H**.

Determine the empirical formula of the following compound if a sample contains 87.5% N and 12.5% H by mass.

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