**Step 1: **40.0% C, 6.7% H, and 53.3% O by mass.** **Recall that ** mass percent** is given by:

$\overline{){\mathbf{\%}}{\mathbf{}}{\mathbf{mass}}{\mathbf{=}}\frac{\mathbf{mass}\mathbf{}\mathbf{of}\mathbf{}\mathbf{X}}{\mathbf{total}\mathbf{}\mathbf{mass}}{\mathbf{\times}}{\mathbf{100}}}$

Assuming we have **100 g** of the compound, this means we have **40.0 g C, 6.7 g H, and 53.3 g O**.

Give the empirical formula of the following compound if a sample contains 40.0% C, 6.7% H, and 53.3% O by mass.

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