Problem: At least 25 µg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2.How many molecules of THC does this 25 µg represent?

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FREE Expert Solution

Molar Mass of THC:


C21H30O2                 21 C x 12.01 g/mol = 252.21 g/mol      

                            30 H x1.01 g/mol = 30.3 g/mol

           2 O x 16.00 g/mol = 32.00 g/mol
            _____________________________
                             Sum = 
314.51 g/mol

        

Avogadro’s number = 6.022 x 1023 entities

                                    entities = atoms, ions, molecules, particles, formula units

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Problem Details

At least 25 µg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2.

How many molecules of THC does this 25 µg represent?

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Based on our data, we think this problem is relevant for Professor Cook's class at LSU.