Problem: At least 25 µg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2.How many molecules of THC does this 25 µg represent?
🤓 Based on our data, we think this question is relevant for Professor Cook's class at LSU.
FREE Expert Solution
Molar Mass of THC:
C21H30O2 21 C x 12.01 g/mol = 252.21 g/mol
30 H x1.01 g/mol = 30.3 g/mol
2 O x 16.00 g/mol = 32.00 g/mol
_____________________________
Sum = 314.51 g/mol
Avogadro’s number = 6.022 x 1023 entities
entities = atoms, ions, molecules, particles, formula units
Problem Details
At least 25 µg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2.
How many molecules of THC does this 25 µg represent?
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What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Cook's class at LSU.