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Molar Mass of THC:
C21H30O2 21 C x 12.01 g/mol = 252.21 g/mol
30 H x1.01 g/mol = 30.3 g/mol
2 O x 16.00 g/mol = 32.00 g/mol
Sum = 314.51 g/mol
Avogadro’s number = 6.022 x 1023 entities
entities = atoms, ions, molecules, particles, formula units
At least 25 µg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2.
How many molecules of THC does this 25 µg represent?
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