Problem: At least 25 µg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2.How many molecules of THC does this 25 µg represent?
FREE Expert Solution
Molar Mass of THC:
C21H30O2 21 C x 12.01 g/mol = 252.21 g/mol
30 H x1.01 g/mol = 30.3 g/mol
2 O x 16.00 g/mol = 32.00 g/mol
_____________________________
Sum = 314.51 g/mol
Avogadro’s number = 6.022 x 1023 entities
entities = atoms, ions, molecules, particles, formula units
Problem Details
At least 25 µg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2.
How many molecules of THC does this 25 µg represent?
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Mole Concept concept. You can view video lessons to learn Mole Concept. Or if you need more Mole Concept practice, you can also practice Mole Concept practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Sommer's class at MIAMIOH.