# Problem: At least 25 µg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2.How many molecules of THC does this 25 µg represent?

###### FREE Expert Solution

Molar Mass of THC:

C21H30O2                 21 C x 12.01 g/mol = 252.21 g/mol

30 H x1.01 g/mol = 30.3 g/mol

2 O x 16.00 g/mol = 32.00 g/mol
_____________________________
Sum =
314.51 g/mol

Avogadro’s number = 6.022 x 1023 entities

entities = atoms, ions, molecules, particles, formula units

83% (45 ratings) ###### Problem Details

At least 25 µg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2.

How many molecules of THC does this 25 µg represent?

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