🤓 Based on our data, we think this question is relevant for Professor Pelton's class at UMN.
We’re being asked to calculate for the mass (grams) of 0.155 mol sucrose (C12H22O11).
Recall that the mass of one mole of any element or compound is equal to its molar mass or molecular weight.
The flow of the solution will be like this:
moles C12H22O11 (molar mass C12H22O11) → mass C12H22O11
Calculate the following quantities.
Mass, in grams, of 0.155 mol sucrose (C12H22O11).