Mass % C:

$\mathbf{\%}\mathbf{}\mathbf{mass}\mathbf{}\mathbf{C}\mathbf{=}\frac{\mathbf{mass}\mathbf{}\mathbf{C}\mathbf{}\mathbf{in}\mathbf{}\mathbf{isopentyl}\mathbf{}\mathbf{acetate}}{\mathbf{molar}\mathbf{}\mathbf{mass}\mathbf{}\mathbf{isopentyl}\mathbf{}\mathbf{acetate}\mathbf{}}\mathbf{\times}\mathbf{100}$

- molar mass C
_{7}H_{14}O_{2}= 130.18 g/mol

Based on the following structural formulas, calculate the percentage of carbon by mass present in each compound.

Isopentyl acetate (banana flavor)

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