Problem: Based on the following structural formulas, calculate the percentage of carbon by mass present in each compound.

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Benzaldehyde

1 mol C7H6O ×1 mol C7H6O1 mol C7H6O×106.118 g C7H6O1 mol C7H6O = 106.118 g C7H6O

1 mol C7H6O ×7 mol C1 mol C7H6O×12.01 g C1 mol C = 84.07 g C


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Problem Details

Based on the following structural formulas, calculate the percentage of carbon by mass present in each compound.

Benzaldehyde (almond fragrance) is a six-carbon (hexagon) ring, with double bonds in alternating sides. The first double bond is in the top. All of the Cs except the right point are single bonded out of the ring to H; the right point is single bonded to a C that is double bonded above to O and single bonded right to H.Vanillin (vanilla flavor) has the same structure as the molecule in part (a), except two additional carbons are single bonded to a group other than H. The C in the left point is single bonded left to OH, and the C in the upper left vertex is single bonded to OCH3.

Isopentyl acetate (banana flavor) is a four carbon chain with all Cs joined by single bonds. The left C is a CH3, the second C is a CH, and the third and fourth Cs are CH2s. The second C is also single bonded below to CH3, and the fourth C is single bonded right to an O that is single bonded right to C. That C is double bonded above to O and single bonded right to CH3.


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