All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: How does the approximate root mean square velocity of neon compare to that of krypton at the same temperature?

Solution: How does the approximate root mean square velocity of neon compare to that of krypton at the same temperature?

Problem

How does the approximate root mean square velocity of neon compare to that of krypton at the same temperature?

Solution

Recall: The root mean square speed of a gas is given by:

where R = universal gas constant (8.314 J/mol K), T = temperature (in K), M = molar mass (in kg/mol). We can see that at a specific temperature, urms is inversely proportional to the molar mass: the higher the molar mass, the lower the urms will be.

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