Problem: How does the approximate root mean square velocity of neon compare to that of krypton at the same temperature?

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Recall: The root mean square speed of a gas is given by:

where R = universal gas constant (8.314 J/mol K), T = temperature (in K), M = molar mass (in kg/mol). We can see that at a specific temperature, urms is inversely proportional to the molar mass: the higher the molar mass, the lower the urms will be.

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How does the approximate root mean square velocity of neon compare to that of krypton at the same temperature?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Root Mean Square Speed concept. You can view video lessons to learn Root Mean Square Speed. Or if you need more Root Mean Square Speed practice, you can also practice Root Mean Square Speed practice problems.

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Based on our data, we think this problem is relevant for Professor Bushey's class at TOWSON.