Assuming 100 g, 39.97 g C, 13.41 g H, 46.62 g N
= 3.33 mol C
= 13.30 mol H
= 3.33 mol N
= 0.25 C
= 1 H
= 0.25 N
You may want to reference (Pages 116 - 119) Section 3.10 while completing this problem.
Determine the molecular formula for the compound with a molar mass of 60.10 g/mol and the following percent compostion:
C:39.97% H:13.41% N:46.62%
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