Problem: You may want to reference (Pages 116 - 119) Section 3.10 while completing this problem.Determine the molecular formula for the compound with a molar mass of 60.10 g/mol and the following percent compostion:C:39.97% H:13.41%  N:46.62%

FREE Expert Solution

Step 1

Assuming 100 g, 39.97 g C, 13.41 g H, 46.62 g N


39.97 g C ×1 mol C12.01 g C = 3.33 mol C

13.41 g H ×1 mol H1.008 g H = 13.30 mol H

46.62 g N ×1 mol N14.01 g N = 3.33 mol N


Step 2


3.33 mol C13.30 mol = 0.25 C

13.30 mol H13.30 mol = 1 H

3.33 mol N13.30 mol = 0.25 N


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Problem Details

You may want to reference (Pages 116 - 119) Section 3.10 while completing this problem.

Determine the molecular formula for the compound with a molar mass of 60.10 g/mol and the following percent compostion:

C:39.97% H:13.41%  N:46.62%

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