$\overline{)\mathbf{molarity}\mathbf{\text{(M)}}\mathbf{=}\frac{\mathbf{moles}\mathbf{}\mathbf{solute}}{\mathbf{L}\mathbf{}\mathbf{solution}}}$

**Calculate moles NaNO _{3}:**

molar mass NaNO_{3} = 85.01 g/mol

$\mathbf{moles}\mathbf{}{\mathbf{NaNO}}_{\mathbf{3}}\mathbf{=}\mathbf{45}\mathbf{.}\mathbf{1}\mathbf{}{\overline{)\mathbf{g}\mathbf{}\mathbf{NaNO}}}_{\mathbf{3}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\mathbf{mol}\mathbf{}{\mathbf{NaNO}}_{\mathbf{3}}}{\mathbf{85}\mathbf{.}\mathbf{01}\mathbf{}\overline{)\mathbf{g}\mathbf{}{\mathbf{NaNO}}_{\mathbf{3}}}}$

**molar mass NaNO _{3} = 0.5305 mol **

**Calculate the molarity of a solution:**

Calculate the molarity of a solution made by adding 45.1 g of NaNO_{3} to a flask and dissolving with water to a total volume of 2.50 L .

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