We will have a double displacement reaction (i.e. cations and anions exchange):
lead (II) nitrate → Pb(NO3)2(aq)
potassium sulfate → K2SO4(aq)
Balanced Reaction: Pb(NO3)2(aq) + K2SO4(aq) → PbSO4(s) + 2KNO3(aq)
• For the total ionic equation → soluble ionic compounds (in aqueous form) separate or breaks up and become ions
• Solids will not break up since they are insoluble compounds
Lead ions can be removed from solution by precipitation with sulfate ions. Suppose that a solution contains lead(II) nitrate.
Enter the complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.
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