# Problem: Lead ions can be removed from solution by precipitation with sulfate ions. Suppose that a solution contains lead(II) nitrate.Enter the complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.

###### FREE Expert Solution

We will have a double displacement reaction (i.e. cations and anions exchange):

Reactants:

lead (II) nitrate   Pb(NO3)2(aq)

potassium sulfate → K2SO4(aq)

Reactants:

lead(II) sulfatePbSO4(s)

potassium nitrateKNO3(aq)

Balanced Reaction: Pb(NO3)2(aq) +  K2SO4(aq) → PbSO4(s) + 2KNO3(aq)

For the total ionic equation  soluble ionic compounds (in aqueous form) separate or breaks up and become ions

• Solids will not break up since they are insoluble compounds

95% (411 ratings) ###### Problem Details

Lead ions can be removed from solution by precipitation with sulfate ions. Suppose that a solution contains lead(II) nitrate.

Enter the complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Complete Ionic Equations concept. You can view video lessons to learn Complete Ionic Equations. Or if you need more Complete Ionic Equations practice, you can also practice Complete Ionic Equations practice problems.