Problem: Lead ions can be removed from solution by precipitation with sulfate ions. Suppose that a solution contains lead(II) nitrate.Enter the complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.

FREE Expert Solution

We will have a double displacement reaction (i.e. cations and anions exchange):

Reactants:

lead (II) nitrate   Pb(NO3)2(aq)

potassium sulfate → K2SO4(aq)

Reactants:

lead(II) sulfatePbSO4(s)

potassium nitrateKNO3(aq)

Balanced Reaction: Pb(NO3)2(aq) +  K2SO4(aq) → PbSO4(s) + 2KNO3(aq)

 For the total ionic equation  soluble ionic compounds (in aqueous form) separate or breaks up and become ions

• Solids will not break up since they are insoluble compounds

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Problem Details

Lead ions can be removed from solution by precipitation with sulfate ions. Suppose that a solution contains lead(II) nitrate.

Enter the complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.

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