# Problem: Lead ions can be removed from solution by precipitation with sulfate ions. Suppose that a solution contains lead(II) nitrate.Enter the complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.

###### FREE Expert Solution

We will have a double displacement reaction (i.e. cations and anions exchange):

Reactants:

potassium sulfate → K2SO4(aq)

Reactants:

potassium nitrateKNO3(aq)

Balanced Reaction: Pb(NO3)2(aq) +  K2SO4(aq) → PbSO4(s) + 2KNO3(aq)

For the total ionic equation  soluble ionic compounds (in aqueous form) separate or breaks up and become ions

• Solids will not break up since they are insoluble compounds

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###### Problem Details

Lead ions can be removed from solution by precipitation with sulfate ions. Suppose that a solution contains lead(II) nitrate.

Enter the complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.