Reaction: 6Li(s) + N_{2}(g) → 2Li_{3}N(s)

Get mol N_{2}:

$\overline{){\mathbf{PV}}{\mathbf{=}}{\mathbf{nRT}}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\frac{\mathbf{PV}}{\mathbf{RT}}{\mathbf{=}}\frac{\mathbf{n}\overline{)\mathbf{RT}}}{\overline{)\mathbf{RT}}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\overline{){\mathbf{n}}{\mathbf{=}}\frac{\mathbf{PV}}{\mathbf{RT}}}$

Lithium reacts with nitrogen gas according to the following reaction: 6Li(s) + N_{2}(g) → 2Li_{3}N(s)

What mass of lithium is required to react completely with 57.6 mL of N_{2} gas at STP?

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