Using Ideal Gas Law:

$\overline{){\mathbf{PV}}{\mathbf{=}}{\mathbf{nRT}}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\frac{\overline{)\mathbf{P}}\mathbf{V}}{\overline{)\mathbf{P}}}{\mathbf{=}}\frac{\mathbf{nRT}}{\mathbf{P}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\overline{){\mathbf{V}}{\mathbf{=}}\frac{\mathbf{nRT}}{\mathbf{P}}}$

Oxygen gas reacts with powdered aluminum according to the following reaction:

4 Al(s) + 3 O_{2}(g) → 2 Al_{2}O_{3}(s)

What volume of O_{2} gas, measured at 778 mmHg and 26 ^{o}C, is required to completely react with 52.6 g of Al?

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