# Problem: Oxygen gas reacts with powdered aluminum according to the following reaction:4 Al(s) + 3 O2(g) → 2 Al2O3(s)What volume of O2 gas, measured at 778 mmHg and 26 oC, is required to completely react with 52.6 g of Al?

###### FREE Expert Solution

Using Ideal Gas Law:

$\overline{){\mathbf{PV}}{\mathbf{=}}{\mathbf{nRT}}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\frac{\overline{)\mathbf{P}}\mathbf{V}}{\overline{)\mathbf{P}}}{\mathbf{=}}\frac{\mathbf{nRT}}{\mathbf{P}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\overline{){\mathbf{V}}{\mathbf{=}}\frac{\mathbf{nRT}}{\mathbf{P}}}$

###### Problem Details
Oxygen gas reacts with powdered aluminum according to the following reaction:

4 Al(s) + 3 O2(g) → 2 Al2O3(s)

What volume of O2 gas, measured at 778 mmHg and 26 oC, is required to completely react with 52.6 g of Al?