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Problem: For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants: 4 Al(s) + 3 O2(g) → 2 Al2O3(s)a. 1 mol Al, 1 mol O2b. 4 mol Al, 2.6 mol O2c. 16 mol Al, 13 mol O2d. 7.4 mol Al, 6.5 mol O2

🤓 Based on our data, we think this question is relevant for Professor Velissaris' class at UCF.

FREE Expert Solution

We are asked to find the limiting reactant for each of the following initial amounts of reactants: 4 Al(s) + 3 O2(g) → 2 Al2O3(s)
a. 1 mol Al, 1 mol O2
b. 4 mol Al, 2.6 mol O2
c. 16 mol Al, 13 mol O2
d. 7.4 mol Al, 6.5 mol O2 


The ratio of Al(s) to O2(g) is 1.33.

  • If the ratio is < 1.33→ Al(s) is limiting
  • If the ratio is > 1.33 → O2(g) is limiting


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Problem Details

For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants: 4 Al(s) + 3 O2(g) → 2 Al2O3(s)
a. 1 mol Al, 1 mol O2
b. 4 mol Al, 2.6 mol O2
c. 16 mol Al, 13 mol O2
d. 7.4 mol Al, 6.5 mol O2

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Velissaris' class at UCF.