2 K(s) + Cl2(g) → 2 KCl(s)
For each of the reactions, calculate the mass (in grams) of the product formed when 15.51 g of the underlined reactant completely reacts. Assume that there is more than enough of the other reactant.
You may want to reference (Pages 141 - 145) Section 4.2 while completing this problem.
K(s) + Cl2(g) → KCl(s)
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