Problem: A gas mixture in a 1.55 L at 301 K container contains 10.0 g of Ne and 10.0 g of Ar.Calculate the partial pressure (in atm) of Ne and Ar in the container.

FREE Expert Solution

Step 1. Calculate the moles of each gas

10 g 1 mol Ne20.18 g = 0.500 mol10 g 1 mol Ar39.95 g = 0.250 mol 

Total moles is: 

0.5 + 0.25 = 0.75 moles

View Complete Written Solution
Problem Details

A gas mixture in a 1.55 L at 301 K container contains 10.0 g of Ne and 10.0 g of Ar.

Calculate the partial pressure (in atm) of Ne and Ar in the container.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the The Ideal Gas Law concept. You can view video lessons to learn The Ideal Gas Law. Or if you need more The Ideal Gas Law practice, you can also practice The Ideal Gas Law practice problems.