Step 1. Calculate the moles of each gas

$10\overline{)\mathrm{g}}\left(\frac{1\mathrm{mol}\mathrm{Ne}}{20.18\overline{)\mathrm{g}}}\right)=0.500\mathrm{mol}\phantom{\rule{0ex}{0ex}}10\overline{)\mathrm{g}}\left(\frac{1\mathrm{mol}\mathrm{Ar}}{39.95\overline{)\mathrm{g}}}\right)=0.250\mathrm{mol}$

Total moles is:

0.5 + 0.25 = 0.75 moles

A gas mixture in a 1.55 L at 301 K container contains 10.0 g of Ne and 10.0 g of Ar.

Calculate the partial pressure (in atm) of Ne and Ar in the container.

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