Problem: A gas mixture in a 1.55 L at 301 K container contains 10.0 g of Ne and 10.0 g of Ar.Calculate the partial pressure (in atm) of Ne and Ar in the container.

FREE Expert Solution

Step 1. Calculate the moles of each gas

10 g 1 mol Ne20.18 g = 0.500 mol10 g 1 mol Ar39.95 g = 0.250 mol 

Total moles is: 

0.5 + 0.25 = 0.75 moles

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Problem Details

A gas mixture in a 1.55 L at 301 K container contains 10.0 g of Ne and 10.0 g of Ar.

Calculate the partial pressure (in atm) of Ne and Ar in the container.

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