Use Charle's Law:

$\overline{)\frac{{\mathbf{V}}_{\mathbf{1}}}{{\mathbf{T}}_{\mathbf{1}}}{\mathbf{=}}\frac{{\mathbf{V}}_{\mathbf{2}}}{{\mathbf{T}}_{\mathbf{2}}}}$

$\frac{{\mathbf{T}}_{\mathbf{2}}\overline{){\mathbf{V}}_{\mathbf{1}}{\mathbf{T}}_{\mathbf{1}}}}{\overline{){\mathbf{V}}_{\mathbf{1}}{\mathbf{T}}_{\mathbf{1}}}}\mathbf{=}\frac{\overline{){\mathbf{T}}_{\mathbf{2}}}{\mathbf{V}}_{\mathbf{2}}{\mathbf{T}}_{\mathbf{1}}}{{{\mathbf{T}}}_{{\mathbf{2}}}{\mathbf{V}}_{\mathbf{1}}}\phantom{\rule{0ex}{0ex}}\overline{){{\mathbf{T}}}_{{\mathbf{2}}}{\mathbf{=}}\frac{{\mathbf{V}}_{\mathbf{2}}{\mathbf{T}}_{\mathbf{1}}}{{\mathbf{V}}_{\mathbf{1}}}}\phantom{\rule{0ex}{0ex}}{\mathbf{T}}_{\mathbf{2}}\mathbf{=}\frac{\left(\mathbf{221}\mathbf{}\overline{)\mathbf{mL}}\right)\left(\mathbf{0}\mathbf{+}\mathbf{273}\mathbf{.}\mathbf{15}\mathbf{}\mathbf{K}\right)}{\left(\mathbf{166}\mathbf{}\overline{)\mathbf{mL}}\right)}$

A gas sample has a volume of 166 mL at 0.00 ^{o}C. The temperature is raised (at constant pressure) until the volume is 221 mL .

What is the temperature of the gas sample in ^{o}C at this volume?

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