Calculate the final pressure using **Boyle's Law**:

$\overline{){\mathbf{P}}_{\mathbf{1}}{\mathbf{V}}_{\mathbf{1}}\mathbf{=}{\mathbf{P}}_{\mathbf{2}}{\mathbf{V}}_{\mathbf{2}}}\phantom{\rule{0ex}{0ex}}$

P_{1} = 753 torr

V_{1} = 280 mL

V_{2} = 280 mL + 480 mL = 760 mL

A 280-mL flask contains pure helium at a pressure of 753 torr . A second flask with a volume of 480 mL contains pure argon at a pressure of 723 torr .

If we connect the two flasks through a stopcock and we open the stopcock, what is the partial pressure of helium?

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