Problem: A 280-mL flask contains pure helium at a pressure of 753 torr . A second flask with a volume of 480 mL contains pure argon at a pressure of 723 torr .If we connect the two flasks through a stopcock and we open the stopcock, what is the partial pressure of helium?

FREE Expert Solution

Calculate the final pressure using Boyle's Law:

$\boxed{{\mathbf{P}}_{\mathbf{1}}{\mathbf{V}}_{\mathbf{1}}\mathbf{=}{\mathbf{P}}_{\mathbf{2}}{\mathbf{V}}_{\mathbf{2}}}$

P₁ = 753 torr

V₁ = 280 mL

V₂ = 280 mL + 480 mL = 760 mL