Problem: A 280-mL flask contains pure helium at a pressure of 753 torr . A second flask with a volume of 480 mL contains pure argon at a pressure of 723 torr .If we connect the two flasks through a stopcock and we open the stopcock, what is the partial pressure of helium?

FREE Expert Solution

Calculate the final pressure using Boyle's Law:

P1V1=P2V2

P1 = 753 torr

V1 = 280 mL

V2 = 280 mL + 480 mL = 760 mL

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Problem Details

A 280-mL flask contains pure helium at a pressure of 753 torr . A second flask with a volume of 480 mL contains pure argon at a pressure of 723 torr .

If we connect the two flasks through a stopcock and we open the stopcock, what is the partial pressure of helium?

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