# Problem: A 280-mL flask contains pure helium at a pressure of 753 torr . A second flask with a volume of 480 mL contains pure argon at a pressure of 723 torr .If we connect the two flasks through a stopcock and we open the stopcock, what is the partial pressure of helium?

###### FREE Expert Solution

Calculate the final pressure using Boyle's Law:

$\overline{){\mathbf{P}}_{\mathbf{1}}{\mathbf{V}}_{\mathbf{1}}\mathbf{=}{\mathbf{P}}_{\mathbf{2}}{\mathbf{V}}_{\mathbf{2}}}\phantom{\rule{0ex}{0ex}}$

P1 = 753 torr

V1 = 280 mL

V2 = 280 mL + 480 mL = 760 mL

82% (202 ratings) ###### Problem Details

A 280-mL flask contains pure helium at a pressure of 753 torr . A second flask with a volume of 480 mL contains pure argon at a pressure of 723 torr .

If we connect the two flasks through a stopcock and we open the stopcock, what is the partial pressure of helium?

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