The reaction is:
Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g)
Fe2O3(s) = 159.69 g/mol
CO(g) = 28.01 g/mol
Fe(s) = 55.85 g/mol
Iron(III) oxide reacts with carbon monoxide according to the equation:
Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2 (g)
A reaction mixture initially contains 22.55 g Fe2O3 and 14.00 g CO.
Once the reaction has occurred as completely as possible, what mass (in g) of the excess reactant remains?
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