Problem: We typically calculate the percent yield using the actual yield and theoretical yield in units of mass (grams or kilograms).Would the percent yield be different if the actual yield and theoretical yield were in units of amount (moles)?

Recall that percent yield is given by the following equation:

$% yield = \frac{actual yield}{theoreticl yield} \times 100$

If calculated using moles:

$% yield = \frac{moles (actual)}{moles (theortical)} \times 100$

But mass can be calculated from moles:

molar mass = g/mol

$mass = mole \times \frac{grams}{mole}$

If calculated using mass:

$% yield = \frac{{(moles \times \frac{grams}{mole})}_{actual}}{{(moles \times \frac{grams}{mole})}_{theoretical}} \times 100$

82% (489 ratings)

We typically calculate the percent yield using the actual yield and theoretical yield in units of mass (grams or kilograms).

Would the percent yield be different if the actual yield and theoretical yield were in units of amount (moles)?

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Percent Yield concept. You can view video lessons to learn Percent Yield. Or if you need more Percent Yield practice, you can also practice Percent Yield practice problems.