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Problem: We typically calculate the percent yield using the actual yield and theoretical yield in units of mass (grams or kilograms).Would the percent yield be different if the actual yield and theoretical yield were in units of amount (moles)?

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Recall that percent yield is given by the following equation:

%yield=actual yieldtheoreticl yield×100


If calculated using moles:

%yield=moles (actual)moles (theortical)×100


But mass can be calculated from moles:

molar mass = g/mol

mass=mole×gramsmole


If calculated using mass:

%yield=(moles×gramsmole)actual(moles×gramsmole)theoretical×100

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Problem Details

We typically calculate the percent yield using the actual yield and theoretical yield in units of mass (grams or kilograms).

Would the percent yield be different if the actual yield and theoretical yield were in units of amount (moles)?

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