Problem: Vanadium forms four different oxides in which the percent by mass of vanadium is respectively 76%, 68%, 61%, and 56%.Give the name of the second oxide.

FREE Expert Solution

Recall that mass percent is given by:

% mass=mass of Xtotal mass×100

Recall that the mass percentages of a compound must add up to 100%. 

This means:

%V + %O = 100%

%O = 100% – 68% = 32% O


Assuming we have 100 g of the compound, this means we have 68 g V and 32 g O.

Now, we need to get the moles of each element in the compound. 

The atomic masses are 50.94 g/mol V and 16.00 g/mol O.

68 g V×1 mol V50.94 g V = 1.33 mol V


32 g O×1 mol O16.00 g O = 2.00 mol O

Divide the number of moles of each by the smallest value.

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Problem Details

Vanadium forms four different oxides in which the percent by mass of vanadium is respectively 76%, 68%, 61%, and 56%.

Give the name of the second oxide.

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