Problem: A 27.6-mL sample of a 1.62 M potassium chloride solution is mixed with 14.6 mL of a 0.890 M lead(II) nitrate solution and this precipitation reaction occurs:2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq)The solid PbCl2 is collected, dried, and found to have a mass of 2.56 g. Determine the limiting reactant, the theoretical yield, and the percent yield.Determine the theoretical yield.

FREE Expert Solution

The limiting reactant is the reactant that produces the least amount of the product.

Reaction: 2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq)

From KCl:

mass PbCl2=27.6 mL KCl(10-3 L1 mL)(1.62 mol KClL)(1 mol PbCl22 mol KCl)(278.1 g PbCl21 mol PbCl2)=6.22 g PbCl2

From Pb(NO3)2:

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Problem Details
A 27.6-mL sample of a 1.62 M potassium chloride solution is mixed with 14.6 mL of a 0.890 M lead(II) nitrate solution and this precipitation reaction occurs:

2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq)


The solid PbCl2 is collected, dried, and found to have a mass of 2.56 g. Determine the limiting reactant, the theoretical yield, and the percent yield.

Determine the theoretical yield.

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