Problem: A sample of Xe takes 75 seconds to effuse out of a container. An unknown gas takes 37 seconds to effuse out of the identical container under identical conditions.What is the most likely identity of the unknown gas?

FREE Expert Solution

Recall that Graham's Law of Effusion allows us to compare the rate of effusion of two gases. Graham's Law states that the rate of effusion of a gas is inversely proportional to its molar mass.


rate=1MMgas,  rate=concentrationtime


This means that when comparing two gases:


rategas 1rategas 2=timegas 2timegas1=MMgas 2MMgas 1


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Problem Details

A sample of Xe takes 75 seconds to effuse out of a container. An unknown gas takes 37 seconds to effuse out of the identical container under identical conditions.

What is the most likely identity of the unknown gas?

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