Problem: Aluminum reacts with chlorine gas to form aluminum chloride.2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)What minimum volume of chlorine gas (at 298 K and 251 mmHg ) is required to completely react with 8.01 g of aluminum?

FREE Expert Solution

2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)

Calculate moles Cl2 using mole-to-mole comparison:

molar mass aluminum (Al) = 26.982 g/mol

moles Cl2=8.01 g Al×1 mol Al26.982 g Al×3 mol Cl22 mol Al

moles Cl2 = 0.4453 mol Cl2


Calculate volume Cl2 using the ideal gas equation:

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Problem Details

Aluminum reacts with chlorine gas to form aluminum chloride.

2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)

What minimum volume of chlorine gas (at 298 K and 251 mmHg ) is required to completely react with 8.01 g of aluminum?

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