2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)
Calculate moles Cl2 using mole-to-mole comparison:
molar mass aluminum (Al) = 26.982 g/mol
moles Cl2 = 0.4453 mol Cl2
Calculate volume Cl2 using the ideal gas equation:
Aluminum reacts with chlorine gas to form aluminum chloride.
2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)
What minimum volume of chlorine gas (at 298 K and 251 mmHg ) is required to completely react with 8.01 g of aluminum?
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