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Problem: Aluminum reacts with chlorine gas to form aluminum chloride.2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)What minimum volume of chlorine gas (at 298 K and 251 mmHg ) is required to completely react with 8.01 g of aluminum?

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2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)

Calculate moles Cl2 using mole-to-mole comparison:

molar mass aluminum (Al) = 26.982 g/mol

moles Cl2=8.01 g Al×1 mol Al26.982 g Al×3 mol Cl22 mol Al

moles Cl2 = 0.4453 mol Cl2


Calculate volume Cl2 using the ideal gas equation:

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Problem Details

Aluminum reacts with chlorine gas to form aluminum chloride.

2 Al(s) + 3 Cl2(g) → 2 AlCl3(s)

What minimum volume of chlorine gas (at 298 K and 251 mmHg ) is required to completely react with 8.01 g of aluminum?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gas Stoichiometry concept. If you need more Gas Stoichiometry practice, you can also practice Gas Stoichiometry practice problems.