The initial and final pressure and volume of the gas are related by ** Boyle’s Law**:

$\overline{){{\mathbf{P}}}_{{\mathbf{1}}}{{\mathbf{V}}}_{{\mathbf{1}}}{\mathbf{=}}{{\mathbf{P}}}_{{\mathbf{2}}}{{\mathbf{V}}}_{{\mathbf{2}}}}$

We can use Boyle’s law as long as the units for the initial and final values are the same.

We can rearrange the combined gas law to solve for P_{2}:

$\overline{){{\mathbf{P}}}_{{\mathbf{2}}}{\mathbf{=}}\frac{{\mathbf{P}}_{\mathbf{1}}{\mathbf{V}}_{\mathbf{1}}}{{\mathbf{V}}_{\mathbf{2}}}}$

A gas sample has an initial pressure of 571 mmHg and an initial volume of 0.526 L .

What is the pressure (in atm) when the volume of the sample is decreased to 226 mL ? (Assume constant temperature and constant number of moles of gas.)

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