Problem: Twenty-five milliliters of liquid nitrogen (density = 0.807 g/mL) is poured into a cylindrical container with a radius of 11.6 cm and a length of 19.6 cm . The container initially contains only air at a pressure of 760.0 mmHg (atmospheric pressure) and a temperature of 298 K .If the liquid nitrogen completely vaporizes, what is the total force (in lb) on the interior of the container at 298 K ?

FREE Expert Solution

We are asked what is the total force (in lb) on the interior of the container at 298 K. 


Calculate the mass of nitrogen: 

25 mL ×0.807 g1 mL  =20.175 g


 Calculate the volume of container: 

V = πr2hV = π(11.6 cm)2(19.6 cm)V = 8285.56 cm3×1 mL1 cm3×10-3 L1 mLV = 8.286 L


Given: 

m = 20.175 g

MM = 28.02 g/mol

R = 0.08206 L-atm/mol-K

T = 298 K

V = 8.286 L

Calculate pressure nitrogen: 

PV = mMMRTP = 20.175 g(28.02  g/ mol)(8.286 L)(0.08206 L-atm mol-K)(298 K)

P = 2.12 atm


Calculate total pressure: 

PT =PN2 + PairPT =2.12 atm+ 1 atmPT =3.12 atm


Calculate surface area of the container: 

A = 2πr2+2πrhA = 2π(11.6 cm)2+2π(11.6 cm)(19.6 cm)A = 2274.01 cm2


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Problem Details

Twenty-five milliliters of liquid nitrogen (density = 0.807 g/mL) is poured into a cylindrical container with a radius of 11.6 cm and a length of 19.6 cm . The container initially contains only air at a pressure of 760.0 mmHg (atmospheric pressure) and a temperature of 298 K .

If the liquid nitrogen completely vaporizes, what is the total force (in lb) on the interior of the container at 298 K ?

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