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Problem: Ammonium carbonate decomposes upon heating according to the following balanced equation: (NH4)2CO3(s) → 2 NH3(g) + CO2(g) + H2O(g). Calculate the total volume of gas produced at 23.0˚C and 1.03 atm by the complete decomposition of 11.9 g of ammonium carbonate.

FREE Expert Solution

Recall the Ideal Gas Law equation:

PV=nRT

Step 1. mol reactant

molar mass of (NH4)2CO3 = 96.09 g/mol

11.9 g (NH4)2CO3×1 mol (NH4)2CO396.09 g (NH4)2CO3=0.124 mol (NH4)2CO3

Step 2. volume of each product

PV=nRTPVP=nRTPV=nRTP

P = 1.03 atm
T = 23.0˚C + 273.15 = 269.15 K
R = 0.08206 (L·atm)/(mol·K)

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Problem Details

Ammonium carbonate decomposes upon heating according to the following balanced equation: (NH4)2CO3(s) → 2 NH3(g) + CO2(g) + H2O(g). Calculate the total volume of gas produced at 23.0˚C and 1.03 atm by the complete decomposition of 11.9 g of ammonium carbonate.

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