Problem: Consider the following reaction:2 SO2 (g) + O2(g) → 2 SO3(g)If 282.8 mL of SO2 is allowed to react with 160.5 mL of O2 (both measured at 316 K and 50.1 mmHg ), what is the limiting reactant?

FREE Expert Solution

Recall the Ideal Gas Law equation:

PV=nRT

Step 1. mole of each reactant

PV=nRTPVRT=nRTRTn=PVRT

P = 50.1 mmHg = 0.066 atm
T = 316 K
R = 0.08206 (L·atm)/(mol·K)

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Problem Details

Consider the following reaction:
2 SO2 (g) + O2(g) → 2 SO3(g)

If 282.8 mL of SO2 is allowed to react with 160.5 mL of O2 (both measured at 316 K and 50.1 mmHg ), what is the limiting reactant?

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