# Problem: Consider the following reaction:2 SO2 (g) + O2(g) → 2 SO3(g)282.8 mL of SO2 is allowed to react with 160.5 mL of O2 (both measured at 316 K and 50.1 mmHg ). If 185.0 mL of SO3 is collected (measured at 316 K and 50.1 mmHg ), what is the percent yield for the reaction?

###### FREE Expert Solution

Recall the Ideal Gas Law equation:

$\overline{){\mathbf{PV}}{\mathbf{=}}{\mathbf{nRT}}}$

Step 1. actual yeild

$\mathbf{PV}\mathbf{=}\mathbf{nRT}\phantom{\rule{0ex}{0ex}}\frac{\mathbf{PV}}{\mathbf{RT}}\mathbf{=}\frac{\mathbf{n}\overline{)\mathbf{RT}}}{\overline{)\mathbf{RT}}}\phantom{\rule{0ex}{0ex}}\overline{){\mathbf{n}}{\mathbf{=}}\frac{\mathbf{PV}}{\mathbf{RT}}}$

P = 50.1 mmHg = 0.066 atm
T = 316 K
R = 0.08206 (L·atm)/(mol·K)

94% (54 ratings) ###### Problem Details

Consider the following reaction:
2 SO2 (g) + O2(g) → 2 SO3(g)

282.8 mL of SO2 is allowed to react with 160.5 mL of O2 (both measured at 316 K and 50.1 mmHg ). If 185.0 mL of SO3 is collected (measured at 316 K and 50.1 mmHg ), what is the percent yield for the reaction?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gas Stoichiometry concept. You can view video lessons to learn Gas Stoichiometry. Or if you need more Gas Stoichiometry practice, you can also practice Gas Stoichiometry practice problems.