Recall the Ideal Gas Law equation:
Step 1. actual yeild
P = 50.1 mmHg = 0.066 atm
T = 316 K
R = 0.08206 (L·atm)/(mol·K)
Consider the following reaction:
2 SO2 (g) + O2(g) → 2 SO3(g)
282.8 mL of SO2 is allowed to react with 160.5 mL of O2 (both measured at 316 K and 50.1 mmHg ). If 185.0 mL of SO3 is collected (measured at 316 K and 50.1 mmHg ), what is the percent yield for the reaction?
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