# Problem: The following picture represents a sample of gas at a pressure of 1 atm, a volume of 1 L, and a temperature of 25 oC. What would happen to the pressure if the volume were reduced to 0.5 L and the temperature increased to 260 oC?

###### FREE Expert Solution

Combined gas law:

$\overline{)\frac{{\mathbf{P}}_{\mathbf{1}}{\mathbf{V}}_{\mathbf{1}}}{{\mathbf{T}}_{\mathbf{1}}}{\mathbf{=}}\frac{{\mathbf{P}}_{\mathbf{2}}{\mathbf{V}}_{\mathbf{2}}}{{\mathbf{T}}_{\mathbf{2}}}}$

The given values are:

P1 = 1 atm
P2 = ??
V1 = 1 L
V2 = 0.5 L
T1 = 25˚C + 273.15 = 298.15 K
T2 = 260˚C + 273.15 = 533.15 K

We can rearrange the combined gas law to solve for P2:

98% (119 ratings) ###### Problem Details

The following picture represents a sample of gas at a pressure of 1 atm, a volume of 1 L, and a temperature of 25 oC What would happen to the pressure if the volume were reduced to 0.5 L and the temperature increased to 260 oC?

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