Combined gas law:
The given values are:
P1 = 1 atm
P2 = ??
V1 = 1 L
V2 = 0.5 L
T1 = 25˚C + 273.15 = 298.15 K
T2 = 260˚C + 273.15 = 533.15 K
We can rearrange the combined gas law to solve for P2:
The following picture represents a sample of gas at a pressure of 1 atm, a volume of 1 L, and a temperature of 25 oC.
What would happen to the pressure if the volume were reduced to 0.5 L and the temperature increased to 260 oC?
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