Problem: The following picture represents a sample of gas at a pressure of 1 atm, a volume of 1 L, and a temperature of 25 oC. What would happen to the pressure if the volume were reduced to 0.5 L and the temperature increased to 260 oC?

FREE Expert Solution

Combined gas law:

P1V1T1=P2V2T2


The given values are:

P1 = 1 atm                    
P2 = ??
V1 = 1 L                    
V2 = 0.5 L
T1 = 25˚C + 273.15 = 298.15 K                       
T2 = 260˚C + 273.15 = 533.15 K


We can rearrange the combined gas law to solve for P2:

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Problem Details

The following picture represents a sample of gas at a pressure of 1 atm, a volume of 1 L, and a temperature of 25 oC

A rectangular prism containing 10 atoms uniformly spaced, all moving around with the same velocity.

What would happen to the pressure if the volume were reduced to 0.5 L and the temperature increased to 260 oC?

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