Calculate the final pressure using **Boyle's Law**:

$\overline{){\mathbf{P}}_{\mathbf{1}}{\mathbf{V}}_{\mathbf{1}}\mathbf{=}{\mathbf{P}}_{\mathbf{2}}{\mathbf{V}}_{\mathbf{2}}}\phantom{\rule{0ex}{0ex}}$

P_{1} = 748 mmHg

V_{1} = 5.1 L

V_{2} = 9.0 L

A sample of gas has an initial volume of 5.1 L at a pressure of 748 mmHg .

If the volume of the gas is increased to 9.0 L , what will the pressure be?

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