Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Sodium reacts with water according to the reaction:2 Na(s) + 2 H2O(l) → 2 NaOH(aq) + H2(g)Identify the oxidizing agent.

Solution: Sodium reacts with water according to the reaction:2 Na(s) + 2 H2O(l) → 2 NaOH(aq) + H2(g)Identify the oxidizing agent.

Problem

Sodium reacts with water according to the reaction:

2 Na(s) + 2 H2O(l) → 2 NaOH(aq) + H2(g)

Identify the oxidizing agent.

Solution
  • Recall the mnemonic GEROA which means Gain Electrons is Reduction = Oxidizing Agent. This tells us that whichever gains electron/s will be considered as the OA
  • Analyze the reactants and product's oxidation number to find who gained electron (became more negative)
  • For the reactants:

Na(s) + H2O(l)

  • Na in Na (s) is 0,  recall that oxidation number of an element in its natural state is zero
  • H2O: H is +1 (H with nonmetal is considered +1) and O is -2 (O is usually -2 except in peroxides and superoxides)


  • For the products:

NaOH(aq) + H2(g)

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