We will have a double displacement reaction (i.e. cations and anions exchange):
KOH(aq) + HNO3(aq) → KNO3(aq) + H2O(l)
Before writing the net ionic equation we need to write the total ionic equation first:
• For the total ionic equation → soluble ionic compounds (in aqueous form) separate or breaks up and become ions
• Solids will not break up since they are insoluble compounds
KOH(aq) → K+(aq) + OH-(aq)
HNO3(aq) ) → H+(aq) + NO3-(aq)
KNO3(aq) → K+(aq) + NO3-(aq)
Total ionic equation: K+(aq) + OH-(aq) + H+(aq) + NO3-(aq → H2O(l)+ K+(aq) + NO3-(aq)
What is the net ionic equation for the reaction that occurs when aqueous solutions of KOH and HNO3 are mixed?
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