# Problem: What is the net ionic equation for the reaction that occurs when aqueous solutions of KOH and ZnCl2 are mixed?

###### FREE Expert Solution

KOH and ZnCl2

KOH(aq) + ZnCl2(aq) →

double displacement reaction:

Reaction:

KOH(aq) + ZnCl2(aq) → KCl + Zn(OH)2

Product:

KCl

Cl- are soluble except when paired with Ag+, Pb2+, Cu+, Hg22+
▪ KCl → soluble → aqueous

Zn(OH)2

Hydroxides (OH-) insoluble except when with Group 1A ions (Li+, Na+, K+, etc.) and ammonium ion (NH4+) and Ca2+, Sr2+, Ba2+
▪ Zn(OH)2 → insoluble → solid/precipitate

Balanced reaction equation:

2 KOH(aq) + ZnCl2(aq) → 2 KCl(aq) + Zn(OH)2(s)

For the total ionic equation → soluble ionic compounds (in aqueous form) separate or breaks up and become ions

• Solids, gases, and liquids will not break up since they are insoluble compounds

Total ionic equation:

80% (249 ratings) ###### Problem Details

What is the net ionic equation for the reaction that occurs when aqueous solutions of KOH and ZnCl2 are mixed?

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