Problem: Sulfur and fluorine react to form sulfur hexafluoride:S(s) + 3 F2(g) → SF6(g)If 50.0 g S is allowed to react as completely as possible with 105.0 g F2(g), what mass of the excess reactant is left?

FREE Expert Solution
83% (490 ratings)
FREE Expert Solution

We first need to determine the moles of SF6 formed by each reactant. The reactant that forms the lower amount of product is the limiting reactant and will dictate the amount of product formed.

83% (490 ratings)
Problem Details

Sulfur and fluorine react to form sulfur hexafluoride:

S(s) + 3 F2(g) → SF6(g)

If 50.0 g S is allowed to react as completely as possible with 105.0 g F2(g), what mass of the excess reactant is left?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. You can view video lessons to learn Limiting Reagent Or if you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems .

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Based on our data, we think this problem is relevant for Professor Dixon's class at UCF.