2 Na(s) + Cl2(g) → 2 NaCl(s)
Calculate the amount of NaCl produced from each reactant and determine the limiting reactant:
mass Na (molar mass) → moles Na (mole-to-mole comparison) → moles NaCl (molar mass) → mass NaCl
molar mass Na = 23.0 g/mol
molar mass NaCl = 58.45 g/mol
mass NaCl = 139.77 g NaCl
mass Cl2 (molar mass) → moles Cl2 (mole-to-mole comparison) → moles NaCl (molar mass) → mass NaCl
Sodium and chlorine react to form sodium chloride:
2 Na(s) + Cl2(g) → 2NaCl(s)
What is the theoretical yield of sodium chloride for the reaction of 55.0 g Na with 67.2 g Cl2?
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