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Problem: Sodium and chlorine react to form sodium chloride:2 Na(s) + Cl2(g) → 2NaCl(s)What is the theoretical yield of sodium chloride for the reaction of 55.0 g Na with 67.2 g Cl2?

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2 Na(s) + Cl2(g) → 2 NaCl(s)

Calculate the amount of NaCl produced from each reactant and determine the limiting reactant:

mass Na (molar mass) → moles Na (mole-to-mole comparison) → moles NaCl (molar mass) → mass NaCl

molar mass Na = 23.0 g/mol
molar mass NaCl = 58.45 g/mol

mass NaCl=55.0 g Na×1 mol Na23.0 g Na×2 mol NaCl2 mol Na×58.45 g NaCl1 mol NaCl

mass NaCl = 139.77 g NaCl


mass Cl2 (molar mass) → moles Cl2 (mole-to-mole comparison) → moles NaCl (molar mass) → mass NaCl

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Problem Details

Sodium and chlorine react to form sodium chloride:

2 Na(s) + Cl2(g) → 2NaCl(s)

What is the theoretical yield of sodium chloride for the reaction of 55.0 g Na with 67.2 g Cl2?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.