Problem: Manganese(IV) oxide reacts with aluminum to form elemental manganese and aluminum oxide:3 MnO2 + 4Al → 3 Mn + 2 Al2O3What mass of Al is required to completely react with 25.0 g MnO2?

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We are asked to calculate the mass of Al is required to completely react with 25.0 g MnO2?


3 MnO2 + 4Al → 3 Mn + 2 Al2O3


Molar mass MnO2 = 86.93 g/mol

Molar mass Al = 26.98 g/mol


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Problem Details

Manganese(IV) oxide reacts with aluminum to form elemental manganese and aluminum oxide:

3 MnO2 + 4Al → 3 Mn + 2 Al2O3

What mass of Al is required to completely react with 25.0 g MnO2?

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Based on our data, we think this problem is relevant for Professor Ratliff's class at USF.