Balanced equation: 4 K(s) + O2 (g) → 2 K2O(s)
Consider the following reaction:
4 K(s) + O2 (g) → 2 K2O(s)
The molar mass of K is 39.09 g/mol and that of O2 is 32.00 g/mol. Without doing any calculations, pick the conditions under which potassium is the limiting reactant. Explain your reasoning.
a) 16 g K, 2.5 g O2
b) 1.5 g K, 0.38 g O2
c) 165 g K, 28 g O2
d) 170 g K, 31 g O2
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.