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Problem: Consider the following reaction:4K(s) + O2 (g) → 2K2O(s)The molar mass of K is 39.09 g/mol and that of O2 is 32.00 g/mol.Without doing any calculations, pick the conditions under which potassium is the limiting reactanta. 170 g K, 31 g O2 b. 16 g K 2.5 g O2  c. 165 kg K 28, Kg O2 d. 1.5 g K 0.38 g O2 

FREE Expert Solution

Estimate the ratio of O2 with K, O2 must be as minimum as possible over K

Analyzing the conditions

a. 170 g K, 31 g O2  → K is approximately 5x more than O

b. 16 g K, 2.5 g O2 → K is approximately 6x more than O2

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Problem Details

Consider the following reaction:

4K(s) + O2 (g) → 2K2O(s)

The molar mass of K is 39.09 g/mol and that of O2 is 32.00 g/mol.

Without doing any calculations, pick the conditions under which potassium is the limiting reactant

a. 170 g K, 31 g O2 

b. 16 g K 2.5 g O2  

c. 165 kg K 28, Kg O2 

d. 1.5 g K 0.38 g O2 

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.