Step 1. total mol
NaCl → Na+ + Cl–
0.0156 mol Cl–
MgCl2 → Mg2+ + 2 Cl–
A solution is prepared by mixing 0.12 L of 0.13 M sodium chloride with 0.24 L of a 0.18 M MgCl2 solution.
What volume of a 0.22 M silver nitrate solution do we need to precipitate all the Cl− ion in the solution as AgCI?
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