We are asked to identify the limiting reactant when a 73.5-g mixture of equal masses of all three reactants is prepared.
2 Au + 2 BrF3 + 2 KF → Br2 +2 KAuF4
Each reactant has 24.5 g. (73.5 g/3)
Molar mass Au = 196.97 g/mol
Molar mass BrF3 = 136.9 g/mol
Molar mass KF =58.1 g/mol
Treatment of gold metal with BrF3 and KF produces Br2 and KAuF4, a salt of gold. Which is the limiting reactant when a 73.5-g mixture of equal masses of all three reactants is prepared?
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