We are asked to identify the limiting reactant when a 73.5-g mixture of equal masses of all three reactants is prepared.
2 Au + 2 BrF3 + 2 KF → Br2 +2 KAuF4
Each reactant has 24.5 g. (73.5 g/3)
Molar mass Au = 196.97 g/mol
Molar mass BrF3 = 136.9 g/mol
Molar mass KF =58.1 g/mol
Treatment of gold metal with BrF3 and KF produces Br2 and KAuF4, a salt of gold. Which is the limiting reactant when a 73.5-g mixture of equal masses of all three reactants is prepared?
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Limiting Reagent concept. If you need more Limiting Reagent practice, you can also practice Limiting Reagent practice problems.