Problem: Treatment of gold metal with BrF3 and KF produces Br2 and KAuF4, a salt of gold.If a 75.0 -g mixture of equal masses is used, how many moles of each reactant is being used?

FREE Expert Solution
  • Setup the balanced equation and determine which will be the limiting reactant using the provided mass of mixture.
  • This mass of mixture has equal amounts of reactant so 75 g must be divided by 3 to get the mass of each reactant.
  • Unbalanced Reaction will appear as:

Au + BrF3 + KF → Br2 + KAuF4

  • Balance Br (2 on both sides)

Au + 2BrF3 + KF → Br2 + KAuF4

  • Balance F (8 on both sides)
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Problem Details

Treatment of gold metal with BrF3 and KF produces Br2 and KAuF4, a salt of gold.

If a 75.0 -g mixture of equal masses is used, how many moles of each reactant is being used?

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Mole Concept concept. You can view video lessons to learn Mole Concept. Or if you need more Mole Concept practice, you can also practice Mole Concept practice problems.