We are asked to find the volume of 0.120 M hydrochloric acid (HCl) necessary to react completely with 1.53 g Al(OH)3.
To do so, we shall follow these steps:
Step 1: Write the balanced chemical reaction.
Step 2: Convert grams into moles of Al(OH)3 using the molar mass of Al(OH)3.
Step 3: Perform a mole-to-mole comparison between HCl and Al(OH)3 (3 mol HCl:1 mol Al(OH)3)
Step 4: Calculate the volume of HCl using the molarity of HCl and moles of HCl.
Find the volume of 0.120 M hydrochloric acid necessary to react completely with 1.53 g Al(OH)3.
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