Assuming we have 1 L solution

**Step 1. **mass of the solution

$\mathbf{1}\mathbf{}\overline{)\mathbf{L}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\overline{)\mathbf{mL}}}{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\overline{)\mathbf{L}}}\mathbf{\times}\frac{\mathbf{1}\mathbf{.}\mathbf{06}\mathbf{}\mathbf{g}}{\overline{)\mathbf{mL}}}\mathbf{=}$**1060 g solution**

Find the percent by mass of sodium chloride in a 1.30 M NaCl solution. The density of the solution is 1.06 g/mL.

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