For the total ionic equation → soluble ionic compounds (in aqueous form) separate or breaks up and become ions
• Solids, gases, and liquids will not break up since they are insoluble compounds
AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)
Total/complete ionic equation:
Ag+(aq) + NO3-(aq) + Na+(aq) + Cl-(aq) → AgCl(s) + Na+(aq) + NO3-(aq)
For the net ionic equation, spectator ions are removed.
Enter the balanced net ionic equation for AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)
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Our tutors have indicated that to solve this problem you will need to apply the Complete Ionic Equations concept. You can view video lessons to learn Complete Ionic Equations. Or if you need more Complete Ionic Equations practice, you can also practice Complete Ionic Equations practice problems.
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Based on our data, we think this problem is relevant for Professor Riehl's class at Minnesota State University - Mankato.